C/C++程序员之家 – 第 64 页 – 关注cplusplus、互联网、程序员的历程–这仅是一个博客，时而无聊，时而搞些研究~

黑客帝国数字雨

By admin | 2012/02/15

批处理简单实现数字雨效果，代码如下：

@echo off
setlocal ENABLEDELAYEDEXPANSION
color 02
for /l %%i in (1,1,80) do (
         set Down%%i=0
)
for /l %%i in (0) do (
set line=
         for /l %%j in (1,1,80) do (
                 set /a Down%%j-=1
                 call set x=!down%%j!
                 if !x! LSS 0 (
                         set /a Arrow%%j=!random!%%6
                         set /a Down%%j=!random!%%15+10
                 )
                 call set x=!Arrow%%j!
                 if "!x!" == "1" (
                         set line=!line!1
                 ) else (set "line=!line! ")
         )
         call set /p=!line!

@echo off

setlocal ENABLEDELAYEDEXPANSION

color 02

for /l %%i in (1,1,80) do (

set Down%%i=0

)

for /l %%i in (0) do (

set line=

for /l %%j in (1,1,80) do (

set /a Down%%j-=1

call set x=!down%%j!

if !x! LSS 0 (

set /a Arrow%%j=!random!%%6

set /a Down%%j=!random!%%15+10

)

call set x=!Arrow%%j!

if "!x!" == "1" (

set line=!line!1

) else (set "line=!line! ")

)

call set /p=!line!

acm大数问题

By admin | 2012/02/13

acm:大数阶乘时间限制：3000 ms | 内存限制：65535 KB 难度：3 描述 …

2011下半年书籍推荐

By admin | 2012/02/13

1.《思科九年》：每一个ie情节的人必看的一本书，通向互联网的金门大桥，思科的传奇！思科，网络的代名词，20…

C/Cplusplus some functions

By admin | 2012/02/13

 One-atoi:<stdlib.h>

 /*atoi example*/   
#include <stdio.h>
#include <stdlib.h>

int main ()
{
  int i;
  char szInput [256];
  printf ("Enter a number: ");
  fgets ( szInput, 256, stdin );
  i = atoi (szInput);
  printf ("The value entered is %d. The double is %d.\n",i,i*2);
  return 0;
}

Two-itoa:<stdlib.h>

// itoa example

#include <stdio.h>
#include <stdlib.h>

int main ()
{
  int i;
  char buffer [33];
  printf ("Enter a number: ");
  scanf ("%d",&i);
  itoa (i,buffer,10);
  printf ("decimal: %s\n",buffer);
  itoa (i,buffer,16);
  printf ("hexadecimal: %s\n",buffer);
  itoa (i,buffer,2);
  printf ("binary: %s\n",buffer);
  return 0;
}

Three-char->string&&string->char:

#include <iostream>

#include <string>

using namespace std;

int main()

{

 string x,temp;
 char p[15]="i am a boy!";
 cin>>x;
 cout<<x.c_str()<<endl;
 temp=p;
 cout<<temp<<endl;

 return 0;

}

Four-sprintf(Formatted data to writing a string)<stdio.h>

#include <iostream>
#include <stdio.h>
using namespace std;
int main()
{
 char str[20];
 sprintf(str,"%d",168);
 cout<<str<<endl;
 sprintf(str,"��",123,457);
 cout<<"Specified width"<<str<<endl;
 sprintf(str,"%8x",123);
 cout<<"width+hexadecimal"<<str<<endl;
 return 0;
}

Five-ceil(返回大于或者等于指定表达式的最小整数)

// ceil example
#include <stdio.h>
#include <math.h>

int main ()
{
  printf ("ceil of 2.3 is %.1lf\n", ceil (2.3) );
  printf ("ceil of 3.8 is %.1lf\n", ceil (3.8) );
  printf ("ceil of -2.3 is %.1lf\n", ceil (-2.3) );
  printf ("ceil of -3.8 is %.1lf\n", ceil (-3.8) );
  return 0;
}
Output:
ceil of 2.3 is 3.0
ceil of 3.8 is 4.0
ceil of -2.3 is -2.0
ceil of -3.8 is -3.0

One-atoi:<stdlib.h>

/*atoi example*/

#include <stdio.h>

#include <stdlib.h>

int main ()

{

int i;

char szInput [256];

printf ("Enter a number: ");

fgets ( szInput, 256, stdin );

i = atoi (szInput);

printf ("The value entered is %d. The double is %d.\n",i,i*2);

return 0;

}

Two-itoa:<stdlib.h>

// itoa example

#include <stdio.h>

#include <stdlib.h>

int main ()

{

int i;

char buffer [33];

printf ("Enter a number: ");

scanf ("%d",&i);

itoa (i,buffer,10);

printf ("decimal: %s\n",buffer);

itoa (i,buffer,16);

printf ("hexadecimal: %s\n",buffer);

itoa (i,buffer,2);

printf ("binary: %s\n",buffer);

return 0;

}

Three-char->string&&string->char:

#include <iostream>

#include <string>

using namespace std;

int main()

{

string x,temp;

char p[15]="i am a boy!";

cin>>x;

cout<<x.c_str()<<endl;

temp=p;

cout<<temp<<endl;

return 0;

}

Four-sprintf(Formatted data to writing a string)<stdio.h>

#include <iostream>

#include <stdio.h>

using namespace std;

int main()

{

char str[20];

sprintf(str,"%d",168);

cout<<str<<endl;

sprintf(str,"��",123,457);

cout<<"Specified width"<<str<<endl;

sprintf(str,"%8x",123);

cout<<"width+hexadecimal"<<str<<endl;

return 0;

}

Five-ceil(返回大于或者等于指定表达式的最小整数)

// ceil example

#include <stdio.h>

#include <math.h>

int main ()

{

printf ("ceil of 2.3 is %.1lf\n", ceil (2.3) );

printf ("ceil of 3.8 is %.1lf\n", ceil (3.8) );

printf ("ceil of -2.3 is %.1lf\n", ceil (-2.3) );

printf ("ceil of -3.8 is %.1lf\n", ceil (-3.8) );

return 0;

}

Output:

ceil of 2.3 is 3.0

ceil of 3.8 is 4.0

ceil of -2.3 is -2.0

ceil of -3.8 is -3.0

Blogroll