a letter and a number

描述

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, … f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

输入

On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).

输出

for each case, you should the result of y+f(x) on a line

样例输入

6 R 1 P 2 G 3 r 1 p 2 g 3

1 2 3 4 5 6 7

6 R 1 P 2 G 3 r 1 p 2 g 3

样例输出

19 18 10 -17 -14 -4

1 2 3 4 5 6

19 18 10 -17 -14 -4

[cpp]
#include “iostream”
using namespace std;
int main()
{
char tc;
int temp,ti;
cin>>temp;
while(temp–)
{
cin>>tc>>ti;
if(tc>=’a’&&tc<='z') cout<<-(tc-96)+ti<=’A’&&tc<='Z') cout<